A can do a work in 20 days. He started the work alone and worked for 12 days then B joins him and completed the remaining work in 4 days. In how many days both A & B working together can complete the whole work?

Question

A can do a work in 20 days. He started the work alone and worked for 12 days then B joins him and completed the remaining work in 4 days. In how many days both A & B working together can complete the whole work?

10
20
12
18

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-04T04:29:57+06:00

Option 1 : 10

Given

A can do a work in 20 days

A started the work alone and worked for 12 days

B joins him and completed the remaining work in 4 days

Formula Used

Work = Time × Efficiency

Where Efficiency = .

Calculation

Let the efficiency of A and B be x and y respectively.

According to the question,

⇒ 20 × x = 12 × x + (x + y) × 4

⇒ 20x = 16x + 4y

⇒ 4x = 4y

⇒ x/y = 1/1

The efficiency of A is 1 and B is 1.

Total work = efficiency of A × Number of days taken by A

⇒ 1 × 20 = 20

Now, A and B complete the work together = (Total work)/(Efficiency of A and B)

⇒ 20/(1 + 1)

⇒ 10 days

∴ Both A & B working together to complete the whole work in 10days.

A can do a work in 20 days. He started the work alone and worked for 12 days then B joins him and completed the remaining work in 4 days. In how many days both A &amp; B working together can complete the whole work?

1 Answers

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A can do a work in 20 days. He started the work alone and worked for 12 days then B joins him and completed the remaining work in 4 days. In how many days both A & B working together can complete the whole work?