There are 48 workers and 2 managers in a company. The salary of one worker of them is twice the salary of another worker. If these 2 workers are replaced by 2 managers whose salaries are Rs. 32000 and Rs. 22000, the average salary of workers increases by Rs. 500. Find the total salary of replaced two workers. ?

Question

There are 48 workers and 2 managers in a company. The salary of one worker of them is twice the salary of another worker. If these 2 workers are replaced by 2 managers whose salaries are Rs. 32000 and Rs. 22000, the average salary of workers increases by Rs. 500. Find the total salary of replaced two workers. ?

Rs. 25000
Rs. 32000
Rs. 30000
Rs. 24000

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-04T04:29:57+06:00

Option 3 : Rs. 30000

Given:

Total number of workers = 48

Number of managers = 2

Formula used:

Sum of observations = Average × Number of observations

Calculation:

Let the average salary of 48 workers be x.

Sum = 48x

Let the salary of one worker be y

Another person salary = 2y

According to the question, we have

⇒ 48x - (y + 2y) + 32000 + 22000 = 48(x + 500)

⇒ 48x - 3y + 54000 = 48x + 24000

⇒ 30000 = 3y

⇒ y = 10000

Another person salary = 2y

⇒ Another person salary = 2 × 10000

⇒ Another person salary = 20000

Total salary = 10000 + 20000

Total salary = 30000

∴ The total salary of the replaced workers is Rs. 30000.