In an irreversible process?

Question

In an irreversible process?

Tds = dE - dW = 0
DE - dW - Tds = 0
Tds - dE + dW
Tds - dT + dW

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-01T13:21:41+06:00

AhmedNazir

Answer: Option 3

From second law of thermodynamics : $$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$ For an irreversible process $$TdS - dU - \delta W > 0$$ And for an reversible process $$TdS - dU - \delta W = 0$$

4 views Answered 2022-09-01 13:21