1. (dF)T, p
  2. (dF)T, p = 0
  3. (dF)T, p > 0
  4. (dA)T, v >0
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1 Answers

Answer: Option 1

Since for an spontaneous process $$Tds > dU + PdV$$ For, constant temperature and constant pressure process the above equation can be written as $$\eqalign{ & d\left( {TS - U} \right) > PdV \cr & \Rightarrow d\left( { - A} \right) > PdV \cr & \Rightarrow {\left( {dF} \right)_{T,\,P}} For spontaneous process. Here the F is Gibbs free energy and A is Helmholtz free energy.

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