1. Sum of the digits is a two-digit number
  2. Digit in the unit's place is half of the digit in the ten's place
  3. Digit in the unit's place and the ten's place are equal
  4. Digit in the unit's place is twice the digit in the ten's place

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Answer: Option 4

Let the ten's digit be x and the unit's digit be y Then, number = 10x + y New number : $$\eqalign{ & = 10 \times 2x + \frac{y}{2} \cr & = 20x + \frac{y}{2} \cr} $$ $$\eqalign{ & \therefore 20x + \frac{y}{2} = 10y + x \cr & \Leftrightarrow 40x + y = 20y + 2x \cr & \Leftrightarrow 38x = 19y \cr & \Leftrightarrow y = 2x \cr} $$ So, the unit's digit is twice the ten's digit.

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