1. 2
  2. 4
  3. 0
  4. 1
  5. 3

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Answer: Option 4

Any four digit number in which first two digits are equal and last two digits are also equal will be in the form 11 × (11a + b) i.e. it will be the multiple of 11 like 1122, 3366, 2244, . . . . Now, let the required number be aabb. Since aabb is a perfect square, the only pair of a and b that satisfy the above mentioned condition is a = 7 and b = 4 Hence, 7744 is a perfect square

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