The height of a Watt's governor (in meters) is equal to (where N = Speed of the arm and ball about the spindle axis)?

$$\frac{{8.95}}{{{{\text{N}}^2}}}$$
$$\frac{{89.5}}{{{{\text{N}}^2}}}$$
$$\frac{{895}}{{{{\text{N}}^2}}}$$
$$\frac{{8950}}{{{{\text{N}}^2}}}$$

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 3

Let'

4 views Answered 2022-09-01 13:21

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