ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?

PB = PC
PB > PC
PB
PB = $$\frac{1}{2}$$ PC

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 1

here given that = AB = AC AQ + BQ = AR + RC we know that BQ = PB & PC = RC AQ + PB = AR + PC also AQ = AR AR + PB = AR + PC PB = PC

4 views Answered 2022-09-01 13:21

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