A point D is taken on the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then?

AB2 + CD2 = AD2 + BC2
CD2 + BD2 = 2AD2
AB2 + AC2 = 2AD2
AB2 = AD2 + BC2

LohaHridoy

6 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 1

According to question, In ΔABC AB2 = AC2 + BC2 . . . . . . . (i) ΔACD AD2 = AC2 + CD2 AC2 = AD2 - CD2 . . . . . . . (ii) Put the value of AC2 in equation (i) AB2 = AD2 - CD2 + BC2 AB2 + CD2 = AD2 + BC2

6 views Answered 2022-09-01 13:21

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