What will be the output class Parent{ public void method(){ System.out.println("Hi i am parent"); } } public class Child extends Parent{ protected void method(){ System.out.println("Hi i am Child"); } public static void main(String args[]){ Child child = new Child(); child.method(); } }?

LohaHridoy
  1. Compiles successfully and print
  2. Compiles successfully and print
  3. Compile time error
  4. Run Time error
  5. None of This

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AhmedNazir

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Answer: Option 3

We cannot reduce the visibility of the inherited method from super class. If the overridden or hidden method is public, then the overriding or hiding method must be public; otherwise, a compile-time error occurs. If the overridden or hidden method is protected, then the overriding or hiding method must be protected or public; otherwise, a compile-time error occurs. If the overridden or hidden method has default (package) access, then the overriding or hiding method must not be private; otherwise, a compile-time error occurs.

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What is the output for the below code public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); } }?

Answer: Option 2 First execute static block, then statement block and then constructor.

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what is the result of the following piece of code: public class Person{ public void talk(){ System.out.print("I am a Person"); } } public class Student extends Person{ public void talk(){ System.out.print("I am a Student"); } } public class Test{ public static void main(String args[]){ Person p = new Student(); p.talk(); } }?

Answer: Option 2 Let'

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1 Answers 87 views
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Answer: Option 1 Let'

1 Answers 5 views
What is the output for the below code import java.io.FileNotFoundException; class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); } } class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); } } public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); } }?

Answer: Option 3 The overriding method can throw any unchecked (runtime) exception, regardless of exception thrown by overridden method. NullPointerException is RuntimeException so compiler will not complain.

1 Answers 1 views
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Answer: Option 1 The options B, C and D are incorrect options as in Java we can declare an abstract class comprising of abstract and non-abstract methods that will not...

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What will be the output class A{ static void method(){ System.out.println("Class A method"); } } class B extends A{ static void method(){ System.out.println("Class B method"); } } public class Test{ public static void main(String args[]){ A a = new B(); a.method(); } }?

Answer: Option 1 Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time...

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What will be the output interface A{ public void method(); } class One{ public void method(){ System.out.println("Class One method"); } } class Two extends One implements A{ public void method(){ System.out.println("Class Two method"); } } public class Test extends Two{ public static void main(String[] args){ A a = new Two(); a.method(); } }?

Answer: Option 2 Let'

1 Answers 4 views
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Answer: Option 2 Let'

1 Answers 1 views
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Answer: Option 4 Let'

1 Answers 3 views
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