- will print Class One method
- will print Class Two method
- compiles fine but print nothing
- Compilation Error
- None of these
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What is the output for the below code public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); } }?
Answer: Option 2 First execute static block, then statement block and then constructor.
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What is the output for the below code class A{ private void printName(){ System.out.println("Value-A"); } } class B extends A{ public void printName(){ System.out.println("Name-B"); } } public class Test{ public static void main (String[] args){ B b = new B(); b.printName(); } }?
Answer: Option 2 You can not override private method , private method is not availabe in subclass . In this case printName() method a class A is not overriding by...
1 Answers 87 views
What is the output for the below code import java.io.FileNotFoundException; class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); } } class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); } } public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); } }?
Answer: Option 3 The overriding method can throw any unchecked (runtime) exception, regardless of exception thrown by overridden method. NullPointerException is RuntimeException so compiler will not complain.
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What will be the output when the following program is compiled and executed abstract class TestAbstract{ String my_name; String myName(){ my_name = "Examveda"; return my_name; } abstract void display(); } public class Test extends TestAbstract{ void display(){ String n = myName(); System.out.print("My name is "+ n); } public static void main(String args[]){ Test t = new Test(); t.display(); } }?
Answer: Option 1 The options B, C and D are incorrect options as in Java we can declare an abstract class comprising of abstract and non-abstract methods that will not...
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What will be the output class A{ static void method(){ System.out.println("Class A method"); } } class B extends A{ static void method(){ System.out.println("Class B method"); } } public class Test{ public static void main(String args[]){ A a = new B(); a.method(); } }?
Answer: Option 1 Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time...
1 Answers 1 views
What happens if the following program is compiled and executed interface MyInterface{ void display(); } interface MySubInterface extends MyInterface{ void display(); } public class Test implements MySubInterface{ public void display(){ System.out.print("Welcome to Examveda."); } public static void main(String args[]){ Test t = new Test(); t.display(); } }?
Answer: Option 3 The program will compile and execute successfully as you can declare methods with same name in an interface and the method of either interface can be used,...
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What will be the output class Parent{ public void method(){ System.out.println("Hi i am parent"); } } public class Child extends Parent{ protected void method(){ System.out.println("Hi i am Child"); } public static void main(String args[]){ Child child = new Child(); child.method(); } }?
Answer: Option 3 We cannot reduce the visibility of the inherited method from super class. If the overridden or hidden method is public, then the overriding or hiding method must...
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