Above the inversion temperature joul thomson coefficient $$\left( \mu \right) = {\left( {\frac{{\partial T}}{{\partial P}}} \right)_H}{\text{ is }} - {\text{ve}}$$
So, on decreasing the pressure (throttling) the temperature increases.
Answer: Option 1
When the air is passed through an insulated chamber having sprays of water maintained at a temperature higher than the dew point temperature of entering air but...
Answer: Option 1
Above the inversion temperature joule-thomson coefficient $${\left( {\frac{{\partial T}}{{\partial P}}} \right)_H} = - ve$$
So, by throttling (decreasing the pressure) the temperature increases and hence heating.
Below the inversion...
Answer: Option 2
For almost all the gases the maximum inversion temperature is above the room temperature but for gases like $${H_2}.$$ The inversion temperatures are 200K and 24K respectively...
Answer: Option 4
Since all the gases except $${H_2}$$ $$He$$ etc, have maximum inversion point greater than atmospheric (room) temperature cooling can take place by throttling if the initial conditions...
Answer: Option 3
For cooling to take place by throttling the Joule-Thomson coefficient must be negative. $${\left( {\frac{{\partial T}}{{\partial P}}} \right)_H} = - VE.$$
Answer: Option 2
Different gases will have different inversion temperatures usually the hydrogen and helium will have very low maximum inversion temperatures so, cooling by using throttling for these gases...
