For cooling to take place by throttling the Joule-Thomson coefficient must be negative. $${\left( {\frac{{\partial T}}{{\partial P}}} \right)_H} = - VE.$$
Answer: Option 3
The joule Thomson coefficient is given as $${\mu _i} = {\left( {\frac{{\partial T}}{{\partial P}}} \right)_H},$$ And since for an ideal gas enthalpy is strictly only function...
Answer: Option 1
Above the inversion temperature joule-thomson coefficient $${\left( {\frac{{\partial T}}{{\partial P}}} \right)_H} = - ve$$
So, by throttling (decreasing the pressure) the temperature increases and hence heating.
Below the inversion...
Answer: Option 2
For almost all the gases the maximum inversion temperature is above the room temperature but for gases like $${H_2}.$$ The inversion temperatures are 200K and 24K respectively...
Answer: Option 4
Since all the gases except $${H_2}$$ $$He$$ etc, have maximum inversion point greater than atmospheric (room) temperature cooling can take place by throttling if the initial conditions...
Answer: Option 1
The sensible heat factor during cooling and dehumidification process is given by (hA - h2)/ (h1 - h2)
where,
h₁ = Enthalpy of air entering the cooling...
Answer: Option 2
The bypass factor, in case of sensible cooling of air, is given by (td₂ -td₃)/( td₁ -td₃)
where td₁ = Dry bulb temperature of air entering the cooling...
