The centre of gravity of the trapezium as shown in below figure from the side is at a distance of?

(h/3) × [(b + 2a)/(b + a)]
(h/3) × [(2b + a)/(b + a)]
(h/2) × [(b + 2a)/(b + a)]
(h/2) × [(2b + a)/(b + a)]

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 1

Let'

5 views Answered 2022-09-01 13:21

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