- $${\text{dt}}{\tau _{\text{u}}}$$
- $$\pi {\text{dt}}{\tau _{\text{u}}}$$
- $$\frac{\pi }{4} \times {{\text{d}}^2}{\tau _{\text{u}}}$$
- $$\frac{\pi }{4} \times {{\text{d}}^2} \times {\text{t}}{\tau _{\text{u}}}$$
Answer: Option 3 Let'
1 Answers 1 viewsAnswer: Option 1 Let'
1 Answers 1 viewsAnswer: Option 4 Let'
1 Answers 1 viewsAnswer: Option 2 Let'
1 Answers 1 viewsAnswer: Option 2 Let'
1 Answers 1 viewsAnswer: Option 4 Let'
1 Answers 1 viewsAnswer: Option 3 Let'
1 Answers 1 viewsAnswer: Option 3 Let'
1 Answers 2 views