What is the output for the below code class A{ int k; boolean istrue; static int p; public void printValue(){ System.out.print(k); System.out.print(istrue); System.out.print(p); } } public class Test{ public static void main(String argv[]){ A a = new A(); a.printValue(); } }?

LohaHridoy
  1. 0 false 0
  2. 0 true 0
  3. 0 0 0
  4. Compile error - static variable must be initialized before use.
  5. None of these

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AhmedNazir

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Answer: Option 1

Global and static variable need not be initialized before use. Default value of global and static int variable is zero. Default value of boolean variable is false. Remember local variable must be initialized before use.

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what is the result of the following piece of code: public class Person{ public void talk(){ System.out.print("I am a Person"); } } public class Student extends Person{ public void talk(){ System.out.print("I am a Student"); } } public class Test{ public static void main(String args[]){ Person p = new Student(); p.talk(); } }?

Answer: Option 2 Let'

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What is the result of compiling and running the following code class Base{ public Base(){ System.out.print("Base"); } } public class Derived extends Base{ public Derived(){ this("Examveda"); System.out.print("Derived"); } public Derived(String s){ System.out.print(s); } public static void main(String[] args){ new Derived(); } }?

Answer: Option 3 1. new Derived(); statement executes and invoke the non-parametrized constructor of derived class i.e. public Derived(); 2. As Derived class is a subclass of class Base so super(); executes...

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What will be the output when the following program is compiled and executed abstract class TestAbstract{ String my_name; String myName(){ my_name = "Examveda"; return my_name; } abstract void display(); } public class Test extends TestAbstract{ void display(){ String n = myName(); System.out.print("My name is "+ n); } public static void main(String args[]){ Test t = new Test(); t.display(); } }?

Answer: Option 1 The options B, C and D are incorrect options as in Java we can declare an abstract class comprising of abstract and non-abstract methods that will not...

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Answer: Option 1 Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time...

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Answer: Option 2 Let'

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Answer: Option 2 Let'

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What will be the output of the following piece of code: class Person{ public void talk() {} } public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); } }?

Answer: Option 1 Let'

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What will be the result after the class Test execution class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); } } class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); } } class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); } } public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } } }?

Answer: Option 4 Let'

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What will be the output after compiling and executing the following code public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); } }?

Answer: Option 3 Let'

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Given the code. What will be the result public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); } }?

Answer: Option 3 Let'

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