3 Answers
a3(b-c)+b3(c-a)+c3(a-b) =a3b-ca3+b3c-ab3+c3(a-b) =a3b-ab3-ca3+b3c+c3(a-b) =ab(a2-b2)-c(a3-b3)+c3(a-b) =(a-b){ab(a+b)-c(a2+ab+b2)+c3} =(a-b)(a2b+ab2-ca2-abc-b2c+c3) =(a-b){a2(b-c)+ab(b-c)-c(b2-c2)} =(a-b)(b-c)(a2+ab-bc-c2) =(a-b)(b-c)(a2-c2+ab-bc) =(a-b)(b-c){(a+c)(a-c)+b(a-c)} =(a-b)(b-c)(a-c)(a+c+b) = -(a-b)(b-c)(c-a)(a+b+c)
3164 views
Answered