2 Answers
3(mx - 1) = 3a(mx - 2)
বা, 3(mx - 1)/3 = a(mx - 2)
বা, 3(mx - 1 - 1) = a(mx - 2)
বা, 3(mx - 2) = a(mx - 2)
বা, 3(mx - 2)/a(mx - 2) = 1
বা, (3/a)(mx - 2) = (3/a)0
অতএব, mx - 2 =0
বা, mx = 2
সুতরাং, x = 2/m
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Answered
3(3mx-1) = 3a(mx-2)
বা, 3(3mx-1)/3 = a(mx-2)
বা, 3(3mx-1)*3-1 = a(mx-2)
বা, 3(3mx-2) = a(mx-2)
বা, log 3(3mx-2) = log a(mx-2)
বা, (3mx-2) log 3 = (mx-2) log a
বা, 3mx log 3 - 2 log 3 = mx log a - 2log a
বা, 3mx log 3 - mx log a = 2log3 - 2log a
বা, x(3m log 3 - m log a) = 2(log 3 – log a)
বা, x = {2 log(3/a)} / {(3m log 3 - m log a)}
বা, x = {2 log(3/a)} / {m (3 log3 – log a)}
বা, x = {2 log(3/a)} / {m (log 33 - log a)}
বা, x = {2 log(3/a)} / {m log (33/a)}
বা, x = {2 log(3/a)} / {m log (27/a)}
বা, 3(3mx-1)/3 = a(mx-2)
বা, 3(3mx-1)*3-1 = a(mx-2)
বা, 3(3mx-2) = a(mx-2)
বা, log 3(3mx-2) = log a(mx-2)
বা, (3mx-2) log 3 = (mx-2) log a
বা, 3mx log 3 - 2 log 3 = mx log a - 2log a
বা, 3mx log 3 - mx log a = 2log3 - 2log a
বা, x(3m log 3 - m log a) = 2(log 3 – log a)
বা, x = {2 log(3/a)} / {(3m log 3 - m log a)}
বা, x = {2 log(3/a)} / {m (3 log3 – log a)}
বা, x = {2 log(3/a)} / {m (log 33 - log a)}
বা, x = {2 log(3/a)} / {m log (33/a)}
বা, x = {2 log(3/a)} / {m log (27/a)}
3986 views
Answered