If the numbers n - 3, 4n - 2, 5n + 1 are in AP, what is the value of n?
If the numbers n - 3, 4n - 2, 5n + 1 are in AP, what is the value of n? Correct Answer 1
Concept:
If a, b, c are in A.P then 2b = a + c
Calculation:
Given:
n - 3, 4n - 2, 5n + 1 are in AP
Therefore, 2 × (4n - 2) = (n - 3) + (5n + 1)
⇒ 8n - 4 = 6n - 2
⇒ 2n = 2
∴ n = 1
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Feb 20, 2025