A right circular solid cone of radius 2.2 cm and height 7.2 cm is melted by recast into a right circular cylinder of height 6.6 cm. What is the square of radius of the base of the cylinder?

A right circular solid cone of radius 2.2 cm and height 7.2 cm is melted by recast into a right circular cylinder of height 6.6 cm. What is the square of radius of the base of the cylinder? Correct Answer 1.76 cm<sup>2</sup>

Given:

radius of cone = 2.2 cm

height of cone = 7.2 cm

height of cylinder = 6.6 cm 

Concept used:

Volume of cone = 1/3(πr2h)

Volume of cylinder = πR2H

Calculation:

1/3(π × r2 × h) = π × R2 × H

⇒ 1/3(2.2 × 2.2 × 7.2) = R2 × 6.6

⇒ 2.2 × 0.8 = R2

∴ R2 = 1.76 cm2

Related Questions

If the given solid metallic right circular cone is melted and recast into a right circular cylinder having the same radius, what would be the height of this cylinder? I. The sum and product of the radius and height of the cone are 31 cm and 147 cm2 respectively. II. Total surface area of the cone is 550 cm2.