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There are three co-prime numbers, the product of first two numbers is 221 and product of last two numbers is 598. What will be the sum of all numbers?

There are three co-prime numbers, the product of first two numbers is 221 and product of last two numbers is 598. What will be the sum of all numbers? Correct Answer 76

Given:

Product of first two numbers = 221

Product of last three numbers = 598

Calculation:

Let the numbers be a, b, and c

According to question ab = 221 and bc = 598

ab/bc = 221/598

⇒ a/c = 17/46    (SIMPLIFIED BY 13)

As the numbers are co-prime

a = 17 and c = 46

As, ab = 221

⇒ 17 × b = 221

⇒ b = 221/17

⇒ b = 13

Then numbers are 17, 13, and 46

Sum of all numbers = 17 + 13 + 46 = 76

∴ Sum of all numbers is 76

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