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What is the minimum angle of deviation produced by a thin prism of angle 4° and refractive index 1.5?

What is the minimum angle of deviation produced by a thin prism of angle 4° and refractive index 1.5? Correct Answer 2° 

CONCEPT:

  • Dispersion of light: The phenomenon in which a white light ray when falls on a prism get separated into its component colors is called dispersion of light.
    •  Different colors of different wavelength experience different degrees of deviation and hence when put through refraction, white light splits into its constituent colors.
    • When light rays fall on the prism then there is a deviation in the path of the ray after refraction through a prism.
    • For a thin prism deviation angle is very small.

The deviation angle (δ) for a thin prism of prism angle A is given by:

δ = (μ-1) A

Where μ is the refractive index of the Prism

CALCULATION:

Given that;

Refractive index (μ) = 1.5

The angle of the prism (A) = 4°

Angle of deviation (δ) = (μ - 1) A = (1.5 - 1) × 4° = 2°

So option 2 is correct.

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