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A 180 liter mixture of syrup and water contains 20% of syrup. What quantity of syrup must be added with that mixture to get 25% syrup?

A 180 liter mixture of syrup and water contains 20% of syrup. What quantity of syrup must be added with that mixture to get 25% syrup? Correct Answer 12 liter

Given:

Total mixture = 180 liter

Syrup contains = 20%

Calculation:

Quantity of syrup in solution = 180 × 20% =180 × (1/5) = 36liter

Quantity of water in mixture = (180 ─ 36) liter = 144 liter

Now in mixture contain 25% of syrup

∴ Water = (100% ─ 25%) = 75%

According to the question,

⇒ 75x = 144

⇒ x = 144/75

∴ Total mixture = 100x liter = 100 × (144/75) = 192 liter

∴ Syrup should be added in mixture = (192 ─ 180) = 12 liter

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