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A conductor 0.2 m long is carrying a current of 20 A at right angles to a magnetic field of 0.5 Tesla. What will be force on the conductor of the current is increased by 50 percent?

A conductor 0.2 m long is carrying a current of 20 A at right angles to a magnetic field of 0.5 Tesla. What will be force on the conductor of the current is increased by 50 percent? Correct Answer 3 N

Concept:

Magnetic force on a current-carrying wire:

  • Magnetic field: The space or region around the current-carrying wire/moving electric charge or around the magnetic material in which force of magnetism can be experienced by other magnetic material is called magnetic field/magnetic induction by that material/current.
  • It is denoted by B.
  • When a current-carrying wire is placed in a magnetic field then it experiences a magnetic force on it.

 

The magnetic force on a current-carrying wire is given by F = BiL Sin θ

Where I = current in a wire, L = length of the wire, B = magnetic field, and θ = angle between current and magnetic field.

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Calculation:

L= 0.2 m

I = 20 A

B = 0.5 T

The current is increased by 50 percent, so

Inew = 20 + 10 = 30 A

F = 30 × 0.2 × 0.5 × sin (90°)

F = 3 N

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