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There are two different ways connected by railway between city A and city B. The first way is 180 km lesser than the second way. Train P travels along the first way and covers the distance between the cities in 10 hours. Train Q travels along the second way and covers the distance in 12 hours. If the speed of train Q is 5 km/hr more than the speed of train P, then, what is the speed of train P (in km/hr)?

There are two different ways connected by railway between city A and city B. The first way is 180 km lesser than the second way. Train P travels along the first way and covers the distance between the cities in 10 hours. Train Q travels along the second way and covers the distance in 12 hours. If the speed of train Q is 5 km/hr more than the speed of train P, then, what is the speed of train P (in km/hr)? Correct Answer 60

Given:

The length of the first way be

The length of the second way will be

Speed of the train P = s km/hr

Speed of the train Q = (s + 5) km/hr

Formula Used:

Speed = Distance/Time

Calculation:

Suppose the length of the first way be x km and so the length of the second way will be (x + 180) km.

Speed of the train P = s km/hr

Speed of the train Q = (s + 5) km/hr

According to question –

⇒ x/s = 10

⇒ x = 10s      ----(i)

Again,

(x + 180)/(s + 5) = 12

⇒ x + 180 = 12(s + 5)

Put the value of x, we have –

⇒ 10s + 180 = 12s + 60

⇒ (12s – 10s) = 180 – 60

⇒ 2s = 120

⇒ s = 60 

∴ The speed of the train P is 60 km/hr.

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