The height of a solid cylinder is 48 cm and the radius of its base is 7 cm. Two identical conical holes each of radius 7 cm and slant height 25 cm are drilled out. What is the surface area (in cm2) of a newly formed solid?

The height of a solid cylinder is 48 cm and the radius of its base is 7 cm. Two identical conical holes each of radius 7 cm and slant height 25 cm are drilled out. What is the surface area (in cm2) of a newly formed solid? Correct Answer 3212 cm<sup>2</sup>

Given:

Height of Cylinder = 48 cm

Radius of Cylinder = 7 cm

Slant Height of Cone = 25 cm

Radius of Cone = 7 cm

Concept used:

The surface area of Remaining Solid = C.S.A of Cylinder + 2(C.S.A of Cone)

Where: C.S.A = Curved Surface Area

Formula used:

The curved Surface area of Cylinder = 2πRH

The curved Surface area of Cone = πrl

Where:

R = Radius of Cylinder, H = Height of Cylinder

r = Radius of Cone, l = slant height of Cone

Calculation:

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Curved Surface area of Cylinder = 2 × (22/7) × 7 × 48 = 2112

Curved Surface area of Cone = (22/7) × 7 × 25 = 550

Surface Area of Remaining Solid = 2112 + 2(550)

⇒ 2112 + 1100 = 3212

∴ The surface area of remaining solid is 3212 cm2.

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