The height of a solid cylinder is 48 cm and the radius of its base is 7 cm. Two identical conical holes each of radius 7 cm and slant height 25 cm are drilled out. What is the surface area (in cm2) of a newly formed solid?
The height of a solid cylinder is 48 cm and the radius of its base is 7 cm. Two identical conical holes each of radius 7 cm and slant height 25 cm are drilled out. What is the surface area (in cm2) of a newly formed solid? Correct Answer 3212 cm<sup>2</sup>
Given:
Height of Cylinder = 48 cm
Radius of Cylinder = 7 cm
Slant Height of Cone = 25 cm
Radius of Cone = 7 cm
Concept used:
The surface area of Remaining Solid = C.S.A of Cylinder + 2(C.S.A of Cone)
Where: C.S.A = Curved Surface Area
Formula used:
The curved Surface area of Cylinder = 2πRH
The curved Surface area of Cone = πrl
Where:
R = Radius of Cylinder, H = Height of Cylinder
r = Radius of Cone, l = slant height of Cone
Calculation:
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Curved Surface area of Cylinder = 2 × (22/7) × 7 × 48 = 2112
Curved Surface area of Cone = (22/7) × 7 × 25 = 550
Surface Area of Remaining Solid = 2112 + 2(550)
⇒ 2112 + 1100 = 3212
∴ The surface area of remaining solid is 3212 cm2.