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In a leap year, January 26th is Saturday. What day will be August 15th in the same year?

In a leap year, January 26th is Saturday. What day will be August 15th in the same year? Correct Answer Friday

26 January of a leap year is Saturday.

The total number of days between 26 January to 15 August is:

Month Name

No. of Days

No. of odd days

January

26

5

February

29(Leap Year)

1

March

31

3

April

30

2

May

31

3

June

30

2

July

31

3

August

15

1

Total odd days

20

 

No. of odd days = 20/7 = 2 weeks and 6 odd days.

26 January is Saturday,

So, Saturday + 6 odd days = Friday.

Hence, "Friday" is the correct answer.

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