The bus fare between two cities is increased in the ratio 9 : 11. What is the increase in the fare, if the original fare is Rs. 675?

The bus fare between two cities is increased in the ratio 9 : 11. What is the increase in the fare, if the original fare is Rs. 675? Correct Answer Rs. 150

Short Trick:

Increase in the fare = 675 × (2/9) = Rs. 150

Detailed Solution:

Let the original fare and increased fare be 9x and 11x respectively

⇒ 9x = 675

⇒ x = 675/9 = 75

Increased fare = 11 × 75 = Rs. 825

∴ Increase in fare = 825 – 675 = Rs. 150

Related Questions

Each of the question below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. If the bus is travelling from Surat to Ahmadabad and a car is travelling from Ahmadabad to Surat, then what is the distance between Surat and Ahmadabad? I. The speed of a car is 40% less than the speed of bus. Bus started at 9 am and car started at 10 am and they meet at 3 pm of the same day. II. After travelling for 1 hour, because of traffic average speed of bus is decreased by 20% and covers distance between Surat to Ahmadabad in 11 hours. Original speed of car is 20% less than original speed of bus and before crossing bus it covered 200 km if starts 1 hour later than bus. After crossing car, bus covers remaining distance in 5 hours. III. Speed of bus is 10 km/hr more than the speed of car and before crossing car ratio of distances covered bus and car in same time was 5 : 4. Time taken by car to cover the distance between Ahmadabad and Surat is 2 hours 15 minutes more than time taken by bus to cover the same distance.