A metal cube of edge 18 cm is melted to form three smaller cubes, which are unequal in dimensions. If the edges of two smaller cubes are 9 cm and 15 cm, what is the surface area in (cm2) of the third smaller cube? 

A metal cube of edge 18 cm is melted to form three smaller cubes, which are unequal in dimensions. If the edges of two smaller cubes are 9 cm and 15 cm, what is the surface area in (cm2) of the third smaller cube?  Correct Answer 864

Given:

Edge of a metal cube = 18 cm

The edge of the two smaller cubes = 9 cm and 15 cm

Formula used:

Volume of cube = a3

Surface area of cube = 6a2

Calculation:

According to the question

Volume of a metal cube = Volume of three smaller cube

⇒ (18)3 = (9)3 + (15)3 + C3

⇒ 5832 = 729 + 3375 + C3

⇒ 5832 = 4104 + C3

⇒ C3 = (5832 – 4104)

⇒ C3 = 1728

⇒ C = 12 cm

Now,

The surface area of cube = (6 × 12 × 12) cm2

⇒ 864 cm2

∴ The surface area of the third smaller cube is 864 cm2

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