A metal cube of edge 18 cm is melted to form three smaller cubes, which are unequal in dimensions. If the edges of two smaller cubes are 9 cm and 15 cm, what is the surface area in (cm2) of the third smaller cube?
A metal cube of edge 18 cm is melted to form three smaller cubes, which are unequal in dimensions. If the edges of two smaller cubes are 9 cm and 15 cm, what is the surface area in (cm2) of the third smaller cube? Correct Answer 864
Given:
Edge of a metal cube = 18 cm
The edge of the two smaller cubes = 9 cm and 15 cm
Formula used:
Volume of cube = a3
Surface area of cube = 6a2
Calculation:
According to the question
Volume of a metal cube = Volume of three smaller cube
⇒ (18)3 = (9)3 + (15)3 + C3
⇒ 5832 = 729 + 3375 + C3
⇒ 5832 = 4104 + C3
⇒ C3 = (5832 – 4104)
⇒ C3 = 1728
⇒ C = 12 cm
Now,
The surface area of cube = (6 × 12 × 12) cm2
⇒ 864 cm2
∴ The surface area of the third smaller cube is 864 cm2
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Feb 20, 2025