A three – bus network is shown in the figure below indicating the p.u. impedance of each element. The bus admittance matrix, Y-bus, of the network is

\(j\left[ {\begin{array}{*{20}{c}} {0.3}&{ - 0.2}&0\\ { - 0.2}&{0.12}&{0.08}\\ 0&{0.08}&{0.02} \end{array}} \right]\)

\(j\left[ {\begin{array}{*{20}{c}} { - 15}&5&0\\ 5&{7.5}&{ - 12.5}\\ 0&{ - 12.5}&{2.5} \end{array}} \right]\)

\(j\left[ {\begin{array}{*{20}{c}} {0.1}&{0.2}&0\\ {0.2}&{0.12}&{ - 0.08}\\ 0&{ - 0.08}&{0.10} \end{array}} \right]\)

\(j\left[ {\begin{array}{*{20}{c}} { - 10}&5&0\\ 5&{7.5}&{12.5}\\ 0&{12.5}&{ - 10} \end{array}} \right]\)

A three – bus network is shown in the figure below indicating the p.u. impedance of each element. The bus admittance matrix, Y-bus, of the network is Correct Answer \(j\left[ {\begin{array}{*{20}{c}} { - 15}&5&0\\ 5&{7.5}&{ - 12.5}\\ 0&{ - 12.5}&{2.5} \end{array}} \right]\)

y₁₁ = -j10

y₁₂ = -j5

y₁₃ = j 12.5

y₃₃ = -j10

y₁₁ = -j15 y₁₂ = j5 y₁₃ = 0

y₂₁ = j5 y₂₂ = j 7.5 y₂₃ = -j12.5

y₃₁ = 0 y₃₂ = -j 12.5 y₃₃ = j 2.5