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A fillet-welded joint is subjected to transverse loading F as shown in the figure. Both legs of the fillets are of 10 mm size and the weld length is 30 mm. If the allowable shear stress of the weld is 94 MPa, considering the minimum throat area of the weld, the maximum allowable transverse load per weld in kN is

A fillet-welded joint is subjected to transverse loading F as shown in the figure. Both legs of the fillets are of 10 mm size and the weld length is 30 mm. If the allowable shear stress of the weld is 94 MPa, considering the minimum throat area of the weld, the maximum allowable transverse load per weld in kN is Correct Answer 19.93

Concept:

Strength of double transverse fillet weld can be calculated by:

P = 2 × 0.707 × (h × l) × σper

where h = leg size, l = length of the single weld.

Calculation:

Given:

h = 10 mm, 2l = 30 mm ⇒ l = 15 mm, τper = 94 MPa

Strength of double transverse fillet weld is:

P = 2 × 0.707 × (h × l) × σper

P = 2 × 0.707 × 0.010 × 0.015 × 94 × 106

P = 19937.4 N = 19.93 kN

[ alt="Mistake Point" src="https://storage.googleapis.com/tb-img/production/19/08/Mistake%20Point.png" style="width: 170px; height: 41px;">

Do not take l = 30 mm, as it is given total weld length which is 2l.

[ alt="26 June 1" src="//storage.googleapis.com/tb-img/production/19/08/26%20June_1.png" style="width: 170px; height: 49px;">

Strength of parallel fillet weld can be calculated by:

P = 0.707 × (h × l) × τper

The nature of stress in the cross-section of a transverse fillet weld is complex due to the weld being subjected to normal stress, shear stress, and bending moment. So, in order to simplify design, many times shear failure is used as a failure criterion. So we can use the equation of load for parallel fillet welds also and it is not necessary to know tensile stress if only shear stress is known.

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