Three pipes A, B, C can individually fill a tank in 45 min., 60 min., and 30 min. respectively. If all the three pipes are simultaneously opened in an empty tank, such that pipes A and B are closed after 9 min. and 12 min. respectively, how much time will pipe C take alone to fill the remaining part of the tank?

Three pipes A, B, C can individually fill a tank in 45 min., 60 min., and 30 min. respectively. If all the three pipes are simultaneously opened in an empty tank, such that pipes A and B are closed after 9 min. and 12 min. respectively, how much time will pipe C take alone to fill the remaining part of the tank? Correct Answer 6 min.

Part filled by A in 1 min. = 1/45

Part filled by B in 1 min. = 1/60

Part filled by C in 1 min. = 1/30

Let the tank is filled in total ‘x’ min.

Pipe A is opened for 9 min., hence, part filled by A in 9 min. = 9 × 1/45 = 1/5

Pipe B is opened for 12 min., hence, part filled by B in 12 min. = 12 × 1/60 = 1/5

Pipe C is opened for x min., hence, part filled by C in x min. = x × 1/30 = x/30

Total work done = 1/5 + 1/5 + x/30 = 1

⇒ x/30 = 3/5

⇒ x = 30 × 3/5 = 18 min.

∴ Pipe C was opened alone for 18 – 12 = 6 min.

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