Three pipes A, B, C can individually fill a tank in 45 min., 60 min., and 30 min. respectively. If all the three pipes are simultaneously opened in an empty tank, such that pipes A and B are closed after 9 min. and 12 min. respectively, how much time will pipe C take alone to fill the remaining part of the tank?
Three pipes A, B, C can individually fill a tank in 45 min., 60 min., and 30 min. respectively. If all the three pipes are simultaneously opened in an empty tank, such that pipes A and B are closed after 9 min. and 12 min. respectively, how much time will pipe C take alone to fill the remaining part of the tank? Correct Answer 6 min.
Part filled by A in 1 min. = 1/45
Part filled by B in 1 min. = 1/60
Part filled by C in 1 min. = 1/30
Let the tank is filled in total ‘x’ min.
Pipe A is opened for 9 min., hence, part filled by A in 9 min. = 9 × 1/45 = 1/5
Pipe B is opened for 12 min., hence, part filled by B in 12 min. = 12 × 1/60 = 1/5
Pipe C is opened for x min., hence, part filled by C in x min. = x × 1/30 = x/30
Total work done = 1/5 + 1/5 + x/30 = 1
⇒ x/30 = 3/5
⇒ x = 30 × 3/5 = 18 min.
∴ Pipe C was opened alone for 18 – 12 = 6 min.