Given below are two quantities named A & B. Based on the given information; you have to determine the relationship between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A: The ratio of marks obtained by Suman and Binoy is 3 : 4. If the combined average of their percentage is 84 and their sum of the marks is 252, find the maximum marks of the exam. Quantity B: Rs. 450 is divided amongst three workers P, Q and R such that 8 times P’s share is equal to 12 times Q’s share which is equal to 6 times R’s share. How much did P get?
Given below are two quantities named A & B. Based on the given information; you have to determine the relationship between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A: The ratio of marks obtained by Suman and Binoy is 3 : 4. If the combined average of their percentage is 84 and their sum of the marks is 252, find the maximum marks of the exam. Quantity B: Rs. 450 is divided amongst three workers P, Q and R such that 8 times P’s share is equal to 12 times Q’s share which is equal to 6 times R’s share. How much did P get? Correct Answer Quantity A = Quantity B or No relation
Quantity A:
∵ Sum of the marks of Suman and Binoy is 252 and ratio of marks obtained by Suman and Binoy is 3: 4;
∴ Marks obtained by Suman = 252 × 3/7 = 108 and
Marks obtained by Binoy = 252 × 4/7 = 144
∴ Combined average marks = (108 + 144)/2 = 126
∵ Combined average of their percentage is 84 and suppose the maximum marks are x;
∴ 84 × x/100 = 126
⇒ x = 12600/84 = 150
∴ Maximum marks of the exam = 150
Alternative method:
Sum of the marks of suman and binoy = 252
Average marks = 252/2 = 126
Now, Combined average of their percentage = 84 (given)
Required Maximum marks = 126/84 × 100 = 150
Quantity B:
Given that:
8P = 12Q = 6R
And (P + Q + R) = 450
Putting the values of Q and R in terms of P:
∴ P + 8P/12 + 8P/6 = 450
⇒ 36P/12 = 450
⇒ P = 150
∴ P gets Rs. 150.
∴ Quantity A = Quantity B