A 4 to 1 multiplexer to realize a Boolean function F (X, Y, Z) is shown in the figure below. The inputs Y and Z are connected to the selectors of the MUX (Y is more significant). The canonical sum-of-product expression for F (X, Y, Z) is

∑m (2, 3, 4, 7)

∑m (1, 3, 5, 7)

∑m (0, 2, 4, 6)

∑m (2, 3, 5, 6)

A 4 to 1 multiplexer to realize a Boolean function F (X, Y, Z) is shown in the figure below. The inputs Y and Z are connected to the selectors of the MUX (Y is more significant). The canonical sum-of-product expression for F (X, Y, Z) is Correct Answer ∑m (2, 3, 4, 7)

F = Y̅ Z̅ I₀ + Y̅ Z I₁ + Y Z̅ I₂ + Y Z I₃

= Y̅ Z̅ X + Y Z̅ X̅ + YZ

= X Y̅ Z̅ + X̅ Y Z̅ + X Y Z + X̅ Y Z

F (X, Y, Z) = ∑m (4, 2, 7, 3)

= ∑m (2, 3, 4, 7)

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Feb 20, 2025

Related Questions

A 4 × 1 multiplexer with two selector lines is used to realize a Boolean function F having four Boolean variables X, Y, Z and W as shown below. S0 and S1 denote the least significant bit (LSB) and most significant bit (MSB) of the selector lines of the multiplexer respectively. I0, I1, I2, I3 are the input lines of the multiplexer. The canonical sum of product representation of F is

F (X, Y, Z, W) = Σ m(0 , 1, 3, 14, 15)

F (X, Y, Z, W) = Σ m( 0, 1, 3,11,14)

F (X, Y, Z, W) = Σ m( 2, 5, 9, 11, 14)

F (X, Y, Z, W) = Σ m(1,3,7,9,15)

Assertion (A) : A multiplexer (MUX) is a device which selects one of the many inputs to a single output. Reason (R): A digital multiplexer is a sequential circuit that selects binary information from one of the many input line sand directs it to a single output line

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true, but (R) is not the correct explanation of (A)

(A) is true, but (R) is false

(A) false, but (R) is true

The propagation delays of the XOR gate, AND gate, and multiplexer (MUX) in the circuit shown in the figure are 4 ns, 2 ns, and 1 ns, respectively. If all the inputs P, Q, R, S, and T are applied simultaneously and held constant the maximum propagation delay of the circuit is

6 ns

7 ns

3 ns

5 ns

A 4 × 1 MUX used to implement a 3-input Boolean function is as shown above. The Boolean function F(A, B, C) implemented is:

F(A, B, C) = ∑(1, 2, 4, 6)

F(A, B, C) = ∑(1, 2, 6)

F(A, B, C) = ∑(2, 4, 5, 6)

F(A, B, C) = ∑(1, 5, 6)

Statement (I): The multiplexer is essentially an electronic switching device which enables each of the inputs to be sampled in turn. Statement (II): A multiplexer is a circuit that is able to have inputs of data from a number of sources and then, by selecting an input channel, gives an output from just one of them.

Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I)

Both Statement (I) and Statement (II) are individually true but Statement (II) is not the correct explanation of Statement (I)

Statement (I) is true but Statement (II) is false

Statement (I) is false but Statement (II) is true

If only one multiplexer and one inverter are allowed to be used to implement any Boolean function of n variables, what is the maximum size of the multiplexer needed?

2^n-2 line to 1 line

2^n-1 line to 1 line

2^{n + 1} line to 1 line

2^{n + 2} line to 1 line

Which of the following statements is/are correct? A. SLR parser is more powerful than LALR parser. B. Canonical LR parser is more powerful than LALR parser. C. LALR parser is more powerful than Canonical LR parser.

Only A

Only B

A and B

A, B and C

Which of the following statements about parser is/are CORRECT? I. Canonical LR is more powerful than SLR. II. SLR is more powerful than LALR. III. SLR is more powerful than Canonical LR.

I only

II only

III only

II and III only

interface Base{ boolean m1 (); byte m2(short s);}

which two code fragments will compile?

1. interface Base2 implements Base {}2. abstract class Class2 extends Base { public boolean m1(){ return true; }}3. abstract class Class2 implements Base {}4. abstract class Class2 implements Base { public boolean m1(){ return (7 > 4); }}5. abstract class Class2 implements Base { protected boolean m1(){ return (5 > 7) }}

1 and 2

2 and 3

3 and 4

1 and 3

4 and 5

If only two bit vectors are allowed to use in the VHDL code, then how many number of MUX will be required to implement 4 to 1 MUX?

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