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30 men can complete a work in 38 days. They work for 25 days then 5 more men joined the group and the work was finished 1 day earlier. How many days would it have been delayed if 5 more men were not joined the group?

30 men can complete a work in 38 days. They work for 25 days then 5 more men joined the group and the work was finished 1 day earlier. How many days would it have been delayed if 5 more men were not joined the group? Correct Answer 1 day

Given:

30 men can complete a work in 38 days. They work for 25 days then 5 more men joined the group and the work was finished 1 day earlier

Concept:

We will use Man-day principle for doing this.

Calculation: 

Let one man do 1 unit of work in one day.

Then 30 men in 38 days do 1140 units work.

Total work = 1140 unit

Work done in 1st 25 days = 30 × 25

Remaining work = 30 × 13

Work was completed in the next 12 days

Those who are already working = 30

Their work in 12 days = 30 × 12 

Remaining work = 30 unit which is done by 5 men

So, Work done by these man in one day = (30/5)/12 =  1/2 unit

If 5 men had not joined  time taken would have been less than 1 day.

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