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Compound A (C9H10O) shows positive iodoform test. Oxidation of A with KMnO4/KOH gives acid B (C8H6O4). Anhydride of B is used for the preparation of phenolphthalein. Compound A is:

Compound A (C9H10O) shows positive iodoform test. Oxidation of A with KMnO4/KOH gives acid B (C8H6O4). Anhydride of B is used for the preparation of phenolphthalein. Compound A is: Correct Answer <img alt="10.04.2019 Shift 2 Synergy JEE Mains D51" src="//storage.googleapis.com/tb-img/production/20/01/10.04.2019%20Shift%202_Synergy_JEE%20Mains_D51.png" style="width: 136px; height: 94px;">

Concept:

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The given compound A (C9H10O) is a ketone which oxidizes under KMnO4/KOH to form carboxylic groups (Phthalic acid) which is B (C8H6O4). When heated gives the anhydride of compound B (Phthalic anhydride) which is used in the preparation of phenolphthalein.

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