12 men or 15 women can do a piece of work in 9 days. If 4 men work on every odd day and 3 women work on every even day. If on the last day of men turn they didn’t come to work and women have to work at the place of men then find in how many days they will complete the work.
12 men or 15 women can do a piece of work in 9 days. If 4 men work on every odd day and 3 women work on every even day. If on the last day of men turn they didn’t come to work and women have to work at the place of men then find in how many days they will complete the work. Correct Answer 103/3 day
Given:
12 men or 15 women can complete the work in 9 days. 4 men and 3 women work alternate day and last day men didn’t come.
Concept:
We will try to solve the question by the LCM method.
Calculation:
12 men can complete the work in 9 days
⇒ 1 man can complete it in 108 days
15 women can complete the work in 9 days
⇒ 1 woman can complete it in 135 days
Let the total work be LCM of 108 and 135 = 540 unit
Efficiency of 1 man = 540/108 = 5 unit
And efficiency of 1 woman = 540/135 = 4 unit
According to question
⇒ 2 days work = (4 men work + 3 women work) = (4 × 5 + 3 × 4) = 32 unit
⇒ 32-days work = 512 unit
Remaining work = 540 - 512 = 28 units which is less than 32 units
⇒ If 12 men work on 33rd day it will be their last day so on 33rd day 3 women will work in place of men.
⇒ 33rd days work = 512 + 12 = 524
⇒ 34th days work = 524 + 12 = 536
Remaining work completed by women in 1/3 day
∴ The total work completed in (34 + 1/3) = 103/3 day.
