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Rathin & Bratin together can complete a piece of work in 12 days. They start the work together but Rathin had to leave 5 days before the work got over. As a result it took a total of 15 days to complete the work. How many days would it have taken Bratin to complete the work by himself?

Rathin & Bratin together can complete a piece of work in 12 days. They start the work together but Rathin had to leave 5 days before the work got over. As a result it took a total of 15 days to complete the work. How many days would it have taken Bratin to complete the work by himself? Correct Answer 30

Given:

Rathin & Bratin complete the work in 12 days.

Formula:

Total work = Efficiency × Time taken

Calculation:

Suppose, Rathin = R and Bratin = B

Let total work be 12 unit

⇒ Efficiency of R and B = 12/12 = 1 units/day

Let Efficiency of B be x units/day

⇒ Efficiency of R = (1 - x) units/day

According to the question

(1 - x) × 10 + 15x = 12

⇒ 10 - 10x + 15x = 12

⇒ 5x = 12 - 10

⇒ x = 2/5

⇒ x = 0.4

Efficiency of Bratin is 0.4 units/day

∴ Bratin alone can complete the whole work in = 12/0.4 = 30 days

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