A man mixes 4 kg of milk costing INR 52.5 per kg with 9 kg of milk costing INR 80 per kg with a sufficient amount of water to make an average value of INR 62 per kg. How many kg of water was added by him?

A man mixes 4 kg of milk costing INR 52.5 per kg with 9 kg of milk costing INR 80 per kg with a sufficient amount of water to make an average value of INR 62 per kg. How many kg of water was added by him? Correct Answer 2 kg

Given:

Mixture: 4 kg milk (Rs. 52.5 per kg), 9 kg milk (Rs. 80 per kg), Water

Final mixture cost = Rs. 62 per kg

Formula used:

Weighted Average = /

Where, n = quantity and A = price

Calculation:

n1 = 4, A1 = 52.5, n2 = 9, A2 = 80, n3 = x (suppose), A3 = 0

Putting values, we get,

62 = /

⇒ 62 = 930 /

⇒ 1 = 15 /

⇒ x = 2 kg

∴ Water added in the mixture = 2 kg

Related Questions

Jar A comprises a mixture of milk and water in the ratio of 3 : 2 respectively. Another mixture of milk and water is added to jar A and the ratio of milk and water in the resultant mixture changes. What was the initial quantity of mixture present in Jar A? I. The ratio of milk and water in the mixture that was added to Jar A was 2 : 1 respectively. II. The ratio of the new quantities of milk and water in Jar A was 8 : 5 respectively. The quantity of water in the mixture added to jar A was 6 litre.