In a work, a man is twice as fast as a woman and a woman is twice as fast as a boy. If all of them, i.e. a man, a woman and a boy together can complete a work in 4 days, then in how many days will a boy alone complete it?

In a work, a man is twice as fast as a woman and a woman is twice as fast as a boy. If all of them, i.e. a man, a woman and a boy together can complete a work in 4 days, then in how many days will a boy alone complete it? Correct Answer 28 days

Given,

1 man, 1 woman and 1 boy together can complete the whole work in = 4 days

Formula :

Total work = Efficiency × Time

Calculation :

Let efficiency of 1 boy be 1 unit/day

Efficiency of woman = 2 units/day

Efficiency of man = 2 × 2 = 4 units/day

Total work = (1 + 2 + 4) × 4 = 28

1 boy alone can complete the whole work in = 28/1 = 28 days

Related Questions