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How many gate(s) would be required to implement the following boolean expression after simplification? Expression: A’(C’D’ + C’D) + AB(C’D’ + C’D) + AB’C’

How many gate(s) would be required to implement the following boolean expression after simplification? Expression: A’(C’D’ + C’D) + AB(C’D’ + C’D) + AB’C’ Correct Answer 1

Boolean expression is: A’(C’D’ + C’D) + AB(C’D’ + C’D) + AB’C’

In simplified form it will be:

= A’ + AB + AB’C’

= A’ + ABC’ + AB’C’                                // As, A + A’ = 1

= A’C’ + AC’(B + B’)

= A’C’ + AC’

= C’(A + A’)= C’
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Therefore, not gate is enough to represent the given Boolean expression.

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