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A man is trying to climb a 6 metre high well – oiled smooth pole. It is also observed that the rate at which he climbs is 2 metres per minute. However, for every minute he climbs, he takes rest for 1 minute before continuing and while resting, he slides down 1 metre. How long will it take for him to reach the top of the pole?

A man is trying to climb a 6 metre high well – oiled smooth pole. It is also observed that the rate at which he climbs is 2 metres per minute. However, for every minute he climbs, he takes rest for 1 minute before continuing and while resting, he slides down 1 metre. How long will it take for him to reach the top of the pole? Correct Answer 9 minutes

Given:

Man is trying to climb 6m high

Rate of climbing a pole = 2m/min

He slips down while resting for 1 min by 1m

Calculation:

For 1st min = climbs 2m

Second min = slips by 1

In 2 min effectively he climbs by just 1m

∴ in 8min he climbs 4m

According to question:

In 9th min he climbs 2m more i.e = (4 + 2)m = 6m

He climbs the pole in 9 min

∴ The required time is 9 min.

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