Five girls – A, B, C, D and E sit in an office in two rows. One row has three chairs and the other row has two chairs. D and E does not sit in one row. A and B does not sit in one row. In how many ways can the five girls be seated?

Five girls – A, B, C, D and E sit in an office in two rows. One row has three chairs and the other row has two chairs. D and E does not sit in one row. A and B does not sit in one row. In how many ways can the five girls be seated? Correct Answer 48

Given:

Five girls – A, B, C, D and E sit in an office in two rows

One row has three chairs and the other row has two chairs

D and E does not sit in one row

A and B does not sit in one row

Concept:

To find the total number of ways of arranging, first the selection has to be done. Then, number of ways of arranging has to be found out.

Calculation:

In the row having two chairs, one among D and E has to be selected. Also, one among A and B has to be selected.

They can be seated in 2! Ways

In the row with three chairs, remaining 3 girls will be seated in 3! = 6 ways

∴ Total number of ways of arranging the five girls = 2 × 2 × 2 × 6 = 48

Hint

Basically, the arrangement can be made in two rows.

In the first row, either 2 or three persons can be seated and vice-versa for the second row.

Hence, in the first row, with D, we can either have one among A, B, or C, or two of them. 

This way, the process continues, and we arrive at 2 × 2 × 2 × 2 × 3 = 48

 

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