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Pipe A and pipe B can fill a tank in 20 hrs and 30 hrs respectively. Pipe C can empty the full tank in 60 hrs. If all three pipes open simultaneously and work for 5 hrs, then after pipe C is closed, then find in how many hrs the remaining tank will be filled?

Pipe A and pipe B can fill a tank in 20 hrs and 30 hrs respectively. Pipe C can empty the full tank in 60 hrs. If all three pipes open simultaneously and work for 5 hrs, then after pipe C is closed, then find in how many hrs the remaining tank will be filled? Correct Answer 8 hrs

Given:

Pipe A can fill a tank in = 20 hrs

Pipe B can fill a tank in = 30 hrs

Pipe C can empty the full tank in = 60 hrs

Formula:

Total work = Efficiency × Time

Calculation:

Let total capacity be 60 units (LCM of 20, 30, and 60)

Efficiency of A = 3 units/hrs

Efficiency of B = 2 units/hrs

Efficiency of C = -1 units/hrs

Total efficiency of A, B and C = 3 + 2 – 1 = 4 units/hrs

Work done by A, B and C in 5 hrs = 4 × 5 = 20 units

Remaining work = 60 – 20 = 40 units

Time taken to fill the remaining tank if only pipe A and B work = 40/5 = 8 hrs

∴ the remaining tank will be filled in 8 hours.

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