A, B and C competed in an ice cream eating contest. A ate 6 scoop in the same time as B ate 4 scoop and C ate 5 scoops. Now A ate 18 scoops in half an hour. How many scoops in total did they eat together in half an hour?

A, B and C competed in an ice cream eating contest. A ate 6 scoop in the same time as B ate 4 scoop and C ate 5 scoops. Now A ate 18 scoops in half an hour. How many scoops in total did they eat together in half an hour? Correct Answer 45

Given:

A ate = 6 scoop

B ate = 4 scoop

C ate = 5 scoop

Scoops are eaten by A in half-hour = 18 scoops

Formula used:

Total work =  Efficiency × Time

(Time × Efficiency × Number of parsons)/work 

Calculation:

⇒ A : B : C = 6 : 4 : 5

⇒ Total efficiency = A + B + C = 6 + 4 + 5 = 15

⇒ (A × time)/work = {(A + B + C) × time}/work

⇒ (6 × 30 min)/18 = (15 × 30 min)/w2

⇒ W2 = 45

∴ A, B and C ate total of 45 scoops in half an hour.

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