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A tiger is 60 of its own leaps behind a deer. The tiger takes 6 leaps per minutes to deer’s 5. If the tiger and the deer cover 10 m and 6 m per leap respectively, then how many leaps will deer cover before being caught by tiger?

A tiger is 60 of its own leaps behind a deer. The tiger takes 6 leaps per minutes to deer’s 5. If the tiger and the deer cover 10 m and 6 m per leap respectively, then how many leaps will deer cover before being caught by tiger? Correct Answer 100 leaps

Calculation:

Speed of Tiger = 6 leaps/min = 6 × 10 m/min = 60 m/min

Speed of Deer = 5 leaps/min = 5 × 6 m/min = 30 m/min

Distance b/w Tiger and Deer at start = 60 × 10 = 600 m

Let d be the distance travelled by deer before being caught by tiger.

Thus, (600 + d)/60 = d/30 ⇒  600 + d = 2d ⇒ d = 600 m

So, the number of leaps covered by deer = 600/6 = 100 leaps

∴ The number of leaps covered by deep is 100 leaps.

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