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Assume that 1. the hour and minute hands of a clock move without jerking. 2. the clock shows a time between 8 o'clock and 9 o'clock 3. the two hands of the clock are one above the other. After how many minute (nearest integer) will the two hands be again lying one above the other?

Assume that 1. the hour and minute hands of a clock move without jerking. 2. the clock shows a time between 8 o'clock and 9 o'clock 3. the two hands of the clock are one above the other. After how many minute (nearest integer) will the two hands be again lying one above the other? Correct Answer 65

When the minute hand travels 60 minutes, the hour hand only travels 5 minutes.
The relative speed between them (both hands in same direction) = 60 - 5 = 55 minutes
They would meet again after = 60 ÷ 55 = 1.09 hours
1.09 hours = 1.09 x 60 = 65.4 minutes

Hence, they would meet again after 65 minutes.

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