500 kg of ore contained a certain amount of steel. After the first blast furnace process, 200 kg of slag containing 12.5% of steel was removed. The percentage of steel in the remaining ore was found to be 20% more than the percentage in the original ore. How many kg of steel were there in the original 500 kg ore?
500 kg of ore contained a certain amount of steel. After the first blast furnace process, 200 kg of slag containing 12.5% of steel was removed. The percentage of steel in the remaining ore was found to be 20% more than the percentage in the original ore. How many kg of steel were there in the original 500 kg ore? Correct Answer 89.2 kg
Calculation:
Initially, ‘x’ kg of steel was there in 500 kg of ore.
Steel in 200 kg of removed slag = 200 × 12.5/100
⇒ 25 kg
The percentage of steel in the remaining ore was found to be 20% more than the percentage in the original ore.
∴ (x – 25)/300 = 120/100 × x/500
⇒ (x - 25)/3 = 12x/50
⇒ 50x – 36x = 1250
⇒ 14x = 1250
⇒ x = 89.2 kg
∴ 89.2 kg of steel were there in the original 500 kg ore.
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Feb 20, 2025