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How many 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

How many 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated? Correct Answer 20

Given:

Digits = 2, 3, 5, 6, 7 and 9

Concept used:

Divisibility rule of 5:

The number is divided by 5, if the unit digit of a number is either 5 or 0.

Calculation:

Unit digit can only be 5.

There is only 1 possible way to fill unit place.

Remaining places can be filled by 2, 3, 6, 7 or 9.

There is 5 possible ways to fill ten's place.

There is 4 possible ways to fill hundredth place as digits cannot be repeated.

Total numbers that can be formed = 1 × 5 × 4 = 20

∴ 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 is 20.

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