Let y[n] = x[n] ∗ h[n], where ∗ denotes convolution and x[n] and h[n] are two discrete time sequences. Given that the z-transform of y[n] is Y(z) = 2 + 3z-1 + z-2, the z-transform of p[n] = x[n] ∗ h[n − 2] is
Let y[n] = x[n] ∗ h[n], where ∗ denotes convolution and x[n] and h[n] are two discrete time sequences. Given that the z-transform of y[n] is Y(z) = 2 + 3z-1 + z-2, the z-transform of p[n] = x[n] ∗ h[n − 2] is Correct Answer 2z<sup>−2</sup> + 3z<sup>−3</sup> + z<sup>−4</sup>
y = x*h
Y(z) = 2 + 3z-1 + z-2
p = x*h
Apply z – transform on both sides
p(z) = X(z) H(z) z-2 → (1)
y = x*h
Apply Z- transform on both sides
Y(z) = X(z).H(z) → (2)
From (1) and (2)
P(z) = (2 + 3z-1 + z-2)z-2 = 2z-2 + 3z-3 + z-4
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Feb 20, 2025