Let y[n] = x[n] ∗ h[n], where ∗ denotes convolution and x[n] and h[n] are two discrete time sequences. Given that the z-transform of y[n] is Y(z) = 2 + 3z-1 + z-2, the z-transform of p[n] = x[n] ∗ h[n − 2] is

Let y[n] = x[n] ∗ h[n], where ∗ denotes convolution and x[n] and h[n] are two discrete time sequences. Given that the z-transform of y[n] is Y(z) = 2 + 3z-1 + z-2, the z-transform of p[n] = x[n] ∗ h[n − 2] is Correct Answer 2z<sup>−2</sup> + 3z<sup>−3</sup> + z<sup>−4</sup>

y = x*h

Y(z) = 2 + 3z-1 + z-2

p = x*h

Apply z – transform on both sides

p(z) = X(z) H(z) z-2 → (1)

y = x*h

Apply Z- transform on both sides

Y(z) = X(z).H(z) → (2)

From (1) and (2)

P(z) = (2 + 3z-1 + z-2)z-2 = 2z-2 + 3z-3 + z-4

Related Questions

What is the sum of impulses in a convolution sum of two discrete time sequences?